If abcd is a rhombus of angle acb=40° then angle ABC=?
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ABC is a an equilateral triangle
hence, angle CAB = angle CAB
therefore angle CAB = 40°
ABC= 180°-(40°+40°)=100°
hence, angle CAB = angle CAB
therefore angle CAB = 40°
ABC= 180°-(40°+40°)=100°
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