Question

If ABCD is a rhombus ,then - answer =(AC)^2+(BD)^2= 4(AB)^2

Answer 1

Step-by-step explanation:

using the pythagorus theorem

ac^2=AB^2+BC^2

BD^2=BC^2+CD^2

adding one and two we have

AC^2+BD^2=AB^2+BC^2+(BC^2+CD^2)

but in a rhombus AB=BC=CD=DA

there AC^2+BD^2=4(AB)^2