Math, asked by swatiswagatika12, 11 months ago

If ABCD is a square find the area of the shaded region.

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swatiswagatika12: Even I don't know the answer.
swatiswagatika12: Plz show me the solution
swatiswagatika12: Okay

Answers

Answered by divergent07
1
see if this helps u .....

if u have options in paper then definitely it wil be less than 19 cm^2
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swatiswagatika12: The common portion of both the quadrant is unshaded . In ur answer u have it in ur shaded portion.
Answered by amitnrw
1

Method to find shaded area is explained

Area of arc with center D = (90/360) π (3)²  m²

Area of arc with center C = (90/360) π (4)²  cm²

Both arc have some unshaded area

Below is method to find unshaded area:

Intersection point of arc = O

Lets draw two straight line DO = 3 cm & CO = 4 cm   (radii)

ΔCOD with sides 3 , 4 and 6 cm

Find angles using cosine rule

∠CDO = α

∠DCO = β

Area of Arc with Center D and angle  α = ( α/360) * 3.14 * 3²

Area of Arc with Center C  and angle  β = ( β/360) * 3.14 * 4²

Find Area of Δ DOC Using Heron formula

Area of unshaded Portion below O = Area of Arc with Center D and angle  α  + Area of Arc with Center C  and angle  β - Area of ΔAPB

Area of Portion x = 18.84 + 18.84 - 15.58 =  22.1 cm²

Area of Shaded region = Area of arc with center D+ Area of arc with center C - 2*Area of unshaded Portion below O

Note: Calculation have not been shown as goes very much in decimals so method being explained to find area of shaded region.

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