If ABCD is a square find the area of the shaded region.
Answers
if u have options in paper then definitely it wil be less than 19 cm^2
Method to find shaded area is explained
Area of arc with center D = (90/360) π (3)² m²
Area of arc with center C = (90/360) π (4)² cm²
Both arc have some unshaded area
Below is method to find unshaded area:
Intersection point of arc = O
Lets draw two straight line DO = 3 cm & CO = 4 cm (radii)
ΔCOD with sides 3 , 4 and 6 cm
Find angles using cosine rule
∠CDO = α
∠DCO = β
Area of Arc with Center D and angle α = ( α/360) * 3.14 * 3²
Area of Arc with Center C and angle β = ( β/360) * 3.14 * 4²
Find Area of Δ DOC Using Heron formula
Area of unshaded Portion below O = Area of Arc with Center D and angle α + Area of Arc with Center C and angle β - Area of ΔAPB
Area of Portion x = 18.84 + 18.84 - 15.58 = 22.1 cm²
Area of Shaded region = Area of arc with center D+ Area of arc with center C - 2*Area of unshaded Portion below O
Note: Calculation have not been shown as goes very much in decimals so method being explained to find area of shaded region.
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