if ABCD is a trapezium in which AB II CD and AD=BC, prove that angle A = angle B
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total area of trapezium =360
ab=cd
ad=bc
ab=180
cd=180
ab= cd
a= 180/2=90
b=180/2=90
a=b
ab=cd
ad=bc
ab=180
cd=180
ab= cd
a= 180/2=90
b=180/2=90
a=b
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