Question

If ∠ ABF = 100 ° ∠adb＝50 Degree The angle cde is equal to 10 degrees, find the degree of the angle daf

Answer 1

Answer:

AO and OB are radii of the circle.

side AO=BO so, ∠OAB=∠OBA [Isosceles triangle AOB]

Angle subtended by chord at the centre of a circle is double of the angle subtended at it's circumference.

Therefore ∠AOB=2∠ACB

∠AOB=100

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In triangle AOB

The sum of all three angle will be 180

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So, ∠AOB+∠OBA+∠OAB=180

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100

∘

+∠OBA+∠OAB=180

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100

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+2∠OAB=180

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[∠OAB=∠OBA]

∠OAB=

2

80

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∠OAB=40

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Step-by-step explanation:

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