Math, asked by Thesmarton3, 9 months ago

if abx^2 = (a^2 - 2ab +b^2)(x+1)
then find find the value of 4/x + 4/x^2 + 1

Answers

Answered by yogeeshwarantn1971
0

Answer:

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Step-by-step explanation:

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Answered by rosoni28
42

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abx² = {(a-b)²}{x+1}

By dividing x^2 on both sides we get,

  • ab = {(a-b)²}{(1/x)+(1/x²)}
  • ab/{(a-b)²} = (1/x)+(1/x²)

Multiply 4 on both sides

  • 4ab/{(a-b)^2} = (4/x) + (4/x^2)

Add 1 on both sides

  • 4ab/{(a-b)²} + 1 = 1 + (4/x) + (4/x²)

Interchange both sides

  • 1 + (4/x) + (4/x²) = {4ab + (a-b)²}/{(a-b)²}
  • = {4ab + a²+ b² - 2ab}/{(a-b)²}
  • = {a² + b² + 2ab}/{(a-b)²}
  • = {(a+b)²}/{(a-b)²}
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