if ac = 2x+5 and bd = 15
abcd is rectangle find x
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Answered by
2
ac=2x+5=15
2x=15-5
2x=10
x=10/2
5
2x=15-5
2x=10
x=10/2
5
Answered by
0
2(l+b)
2(2x+5+15)
2(2x+20)
4x+40
-40=4x
-40/4=x
-10=x
2(2x+5+15)
2(2x+20)
4x+40
-40=4x
-40/4=x
-10=x
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