Math, asked by srikanthchiku4835, 8 months ago

If AC=8cm AB=6cm then area of semicircle drawn on the hypotenuse is

Answers

Answered by kushsingh2004
0

Answer:

39.25 square cm.

Step-by-step explanation:

BC=√(8^2 + 6^2)

=√100

=10

Therefore BC = 10cm

Also BC= diameter of the semicircle.

therefore radius = 5cm

therefore area of semicircle is

π×(5)^2 /2

=39.25 square cm. (π=3.14)

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