If AC=BD prove that AD=BC
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Step-by-step explanation:Since in triangles ACD and BDC
AD=BC (given)
CD=CD (common)
Angle(ADC)=Angle(BCD){angles formed by the same segment in a circle, are equal.}
Hence, these ∆s are congruent(A.S.S)
Thus AC=BD(c.p.c.t.)
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