if AC = BD, then prove that AB = CD
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AC=BD
AC-BC=BD-BC
AB=CD
AC=BD
AC-BC=BD-BC
AB=CD
siri2468:
hi
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AC=BD
AB+BC=BC+CD
Therefore, AB=CD (THINGS WHICH ARE EQUAL TO THE SAME THING ARE EQUAL TO EACH OTHER)
AB+BC=BC+CD
Therefore, AB=CD (THINGS WHICH ARE EQUAL TO THE SAME THING ARE EQUAL TO EACH OTHER)
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