if AC>AB and AD is the bisector of ∠A,show that ∠ADC>∠ADB.
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Given: AC>AB
and AD is bisector of angle A
⇒angleBAD = angle CAD = Angle A/2
Also in triangle ABD
angle ABD+ angleBAD + angle ADB = 180 degree
⇒angle ADB = 180-angle ABD + Angle A/2
Now, angle ABD> angle ACD ...(∵ angle opposite to longer side is greater)
⇒angle ABD +angle A/2 > angle ACD + angle A/2
⇒180-angle ACD + angle A/2 > 180-angle ABD +angle A/2
⇒angle ADC > angle ADB
and AD is bisector of angle A
⇒angleBAD = angle CAD = Angle A/2
Also in triangle ABD
angle ABD+ angleBAD + angle ADB = 180 degree
⇒angle ADB = 180-angle ABD + Angle A/2
Now, angle ABD> angle ACD ...(∵ angle opposite to longer side is greater)
⇒angle ABD +angle A/2 > angle ACD + angle A/2
⇒180-angle ACD + angle A/2 > 180-angle ABD +angle A/2
⇒angle ADC > angle ADB
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