Question

If acosθ +bcosθ =m and bcosθ -acosθ =n,then what will be the value of a^2+b^2...No spam

Answer 1

Answer:

There is a mistake in this question.

I.e y= a cos theta - b sin theta

It will be solved as:

Take x^2 + y^2

=a^2sin^2theta+b^2cos^2theta+2ab sin theta cos theta + a^2cos^2theta + b^2sin^2theta-2ab Sin theta cos theta

=a^2(sin^2theta + cos^2theta) + b^2(cos^2theta + sin^2theta)

=a^2(1) + b^2(1)

=a^2 + b^2= rha

Answer 2

Step-by-step explanation:

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