Math, asked by trishaboda, 9 months ago

If acos3α+3acosαsin2α =m;asin3α +3acos2αsinα=n then value of (m+n)2/3+(m−n)2/3=

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Answered by rakeshpilania59662
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Answer:

If acos3α+3acosαsin2α =m;asin3α +3acos2αsinα=n then value of (m+n)2/3+(m−n)2/3=

Step-by-step explanation:

If acos3α+3acosαsin2α =m;asin3α +3acos2αsinα=n then value of (m+n)2/3+(m−n)2/3=If acos3α+3acosαsin2α =m;asin3α +3acos2αsinα=n then value of (m+n)2/3+(m−n)2/3=

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