if action is always equal and opposite to reaction then how a horse is able to pull the cart
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When Horse is pulling a cart he apply friction force on earth backward. As result of reaction he able to move forward.
Abishekp:
that is by "Newton's third law of motion
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there are many components not just action and rxn.
in this case force applied by horse is action and friction is rxn. now there is a term called static friction. static friction is the force acting between 2 surface of contact when 1 surface of contact is in rest relative to other. now static friction has a limit, called limiting friction. it is the maximum value of static friction. if the horse is able to exert force that is higher in magnitude than the limiting friction the cart moves. in brief for your question, when horse pulls the cart the net force ;
force(horse)-force(rxn force of cart)=non zero term
then the cart moves
in this case force applied by horse is action and friction is rxn. now there is a term called static friction. static friction is the force acting between 2 surface of contact when 1 surface of contact is in rest relative to other. now static friction has a limit, called limiting friction. it is the maximum value of static friction. if the horse is able to exert force that is higher in magnitude than the limiting friction the cart moves. in brief for your question, when horse pulls the cart the net force ;
force(horse)-force(rxn force of cart)=non zero term
then the cart moves
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