Question

If AD is parallel to BC,angle DAB =90 ,AD=10,BC=4 and ABE is a quadrant of a circle find the area of the shaded region

Answer 1

Answer:

Given: trapezium ABCD, ∠DAB=90

∘

, AD=10, BC=4 cm ,Area=24.5 sq.cm

Area of trapezium =

2

1

(Sum of parallel sides) (Perpendicular)

24.5=

2

1

×(10+4)×AB

AB=3.5

Area of quadrant ABE=

360

θ

π(AB)

2

Area of quadrant ABE=

360

90

×

7

22

(3.5)

2

Area of quadrant ABE= 9.625cm

2

Area of shaded portion = Area of trapezium − Area of quadrant ABE

Area of shaded portion = 24.5−9.625

Area of shaded portion = 14.375 cm

2

=14 cm

2

(rounding off to the nearest integer)

Step-by-step explanation:

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