Question

If AD is the median of the triangle abc then

Answer 1

Answer:

In a triangle ABC ,if AD is the mediun than show that AB2 +AC2 =2( AD2 +BD2) AD is a mediun of ∆ ABC.

Answer 2

$If \: AD \: is \: the \: median \: of \: the \\triangle \: ABC \: then \\</p><p>\blue { it \: divides \: it \: into \: two \: triangles}\\ \blue { of \: equal \:area .}$

$From \:the \: figure,$

$AD\: is \:one \: of \: median \:of \:\triangle ABC$

$\green { Area ( \triangle ABD) =Area ( \triangle ACD) }$

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