Question

if ad not equal to bc then what is the solution of ax+by=p nd cx+dy=q​

Answer 1

x = (dp - bq)/(ad - bc) , y = (aq - bp)/(ad - bc)  is the solution of ax+by=p nd cx+dy=q​ if ad ≠ bc

Step-by-step explanation:

ad ≠ bc

ax + by = p    Eq1

cx + dy = q    Eq2

d * eq1 - b * eq2

=> adx  - bcx  = dp - bq

=> x(ad - bc) = dp - bq

=> x = (dp - bq)/(ad - bc)

a*eq2  - c * eq1

=> ady - bcy  =  aq  - bp

=> y(ad - bc) = aq - bp

=> y = (aq - bp)/(ad - bc)

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