Question

If Aditya travels to school from his home at the speed of 3 km/hr, then
reaches school 5 minutes late. At the speed of 4 km/hr he reaches school 5 minut
early. Find the distance between his home and school.​

Answer 1

Step-by-step explanation:

let the distance between his home and the school be D km

and time taken be x hours

when he is late he takes x + 5/60hr

when he is early he takes x - 5/60hr

when he is late he travels with a speed of 3km/hrs

when he is early he travels with 4km/hrs

distance = speed × time

3(x + 5/60) = 4(x - 5/60)

12x + 1/4 = 12x -1 / 3

36x + 3 = 48x - 4

7/ 12 = x

distance = 3 × 7/12

= 3/4