Math, asked by ashishoo5723, 1 year ago

If adjacent side of the rectangle is 2x+3y–2 and 3x+y–1 then find it perimeter

Answers

Answered by surajsharma0096
1
The adjacent side of the rectangle is 2x+3y-2 and 3x+y-1.

Perimeter =2(2x+3y-2 + 3x+y-1)
=4x+6y-4 +6x+2y-2
=4x+6x+6y+2y-4-2
=10x + 8y -2

.:The perimeter of the rectangle =10x +8y -2

Similar questions