Question

if AE=CB and DE=CD,then prove that D is the midpoint of the line segment AB

Answer 1

AE = CB..............(Given).............I
DE = CD..............(Given)............II
Subtracting II from I we get ,
AE-DE =  CB-CD......(additive property of equality)
AD = DB
So, AD+DB=AB 
Therefore, the distance between AD and DB is same.
So, D is the mid-point of the line segment AB.