If ai+aj+ck and i+k and ci+cj+bk are coplanar then show that c^2=ab
Answers
Answered by
13
I think that the answer is this.
Attachments:
Answered by
6
Answer:
we need to show c²=ab if ai+aj+ck and i+k and ci+cj+bk are co-planar
The three vectors are co-planar if their scalar triple product is zero.
a(0-c) - a(b-c) + c(c-0)=0
a(-c) - a(b-c) + c(c) = 0
-ac - ab + ac + c²=0
- ab + c²=0
add both the sides by ab, in above expression
c² = ab
Hence proved
Similar questions
Math,
6 months ago
Hindi,
6 months ago
Psychology,
1 year ago
Science,
1 year ago
Geography,
1 year ago