If alf and bita are roots of the equation 3x²+8x+2=0
then find the value of 1/Alfa +1\bita
Answers
Answered by
2
Answer:let alfa=a and beeta=b
1/a+1/b=b+a/ab
a+b=-8/3
ab=2/3
1/a+1/b=-8/3/2/3
=-4
Answered by
1
Answer:
Step-by-step explained
Here a = 3, b = 8, and c = 2
Therefore,
Alfa= -b/a
= 8/3
Bita= c/a
= 2/3
So, putting the value of Alfa and Bita
Therefore,
1/8/3+1/2/3
= 3/8+3/2
= 3+12/8
= 15/8
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