Question

if alfa and beeta are the zeros of the quadratic polynomial f(x)=ax2+bx+c,then evaluate 1/alfa.1/beta​

Answer 1

HEY MATE !!!

$f(x) = a {x}^{2} + bx + c$

$\frac{1}{ \alpha } + \frac{1}{ \beta } \\ = \frac{ \beta + \alpha }{ \alpha \beta } \\(lcm)$

$\frac{ \alpha + \beta }{ \alpha \beta } \\ \frac{ \frac{ - b}{c} }{ \frac{a}{c} } \\ = \frac{ - b}{c} \times \frac{c}{a} \\ = \frac{ - b}{a}$

Answer 2

the value of evaluate 1/alfa.1/beta is = a/c

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