Question

if alfa and beta are complimentary angles,then value of sin^2(theta upon 2 -alfa)+sin^2(theta upon 2-beta) is equal to: (A) 1/2 (B)3/2 (C)3/4 (D)1 ​

Answer 1

Answer:

option(D) 1

Step-by-step explanation:

sin²(θ/2 -α)+sin²(θ/2+β)

let θ/2 -α=A and θ/2+β=B

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Here B= θ/2+β

=θ/2+90-α

=90+θ/2-α

B=90+A

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so sin²(θ/2 -α)+sin²(θ/2+β)

= sin²A+sin²(90+A)

=sin²A+cos²A

=1

option(D)

Answer 2

Answer:

option D

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