If Alfa and bita are the roots 9f quadratic equation 3x square+Kx+8=0 and Alfa upon bita = 2/3,then find the value of k
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alp / bet. = 2/ 3
3alp. = 2bet.
alp. = 2/3 bet.
alp. * bet. = c/a
2*bet. * bet / 3 = 8 /3
2beta. ^2 = 8
Beta^2 = 4 so, beta = 2
And alpha = 4/ 3
Alpha + beta = - b/a
4/3 +2 = -k /3
10/3 = -k/3
K = -10
I haven't shown root 4 as - 2 .
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