Question

if alfa,bita,gema is zeros of polynomials ax³+bx²+cx+d so find 1/(alfa)(bita)+1/(bita)(gema)+1/(gema)(alfa)=​

Answer 1

Step-by-step explanation:

$\alpha \: , \beta \: ,\gamma \: is \: zeros \: of \: the \: given \: \\ polynomial \: \: \: then \\ \\ \alpha + \beta + \gamma = - \frac{b}{a} \\ \alpha \beta \gamma = - \frac{d}{a} \\ \\ \frac{1}{ \alpha \beta } + \frac{1}{ \beta \gamma } + \frac{1}{ \alpha \gamma } = \frac{ \alpha + \beta + \gamma }{ \alpha \beta \gamma } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{b}{d} \\ \\ \\ hope \: it \: will \: help \: you.....$