Math, asked by akankshamadigela, 1 month ago

if all face cards are removed from a pack of 52 playing cards and well shuffled then what is the probability of picking a card with a red even number and a club odd number and a Jack and a prime number

Answers

Answered by himanisinghal625
0

Answer:

suppose red even no. are 10

so it's probability is 10/52

odd number is 19

so it's probability is 19/52

Answered by prishaagrahari
0

Cards bearing numbers 2, 3, 4, 5, 6, 7, 8, 9 and 10 are numbered cards in the pack of 52 playing cards. <br> The cards whose numbers are multiples of 3 are 3, 6 and 9. <br> As each suit has one '3', one '6' and one '9', therefore, in total we have four 3's, four 6's and four 9's. <br>

Total number of cards whose numbers are multiples of 3 = 12. <br> On removing these cards from the pack, the number of cards left in the pack = 52 - 12 = 40. <br> (i) As each suit has one king, one queen and one jack, therefore, in total we have 4 kings, 4 queens and 4 jacks. <br>

Total number of face cards in the pack = 12. <br>

The number of outcomes favourable to the event 'a face card' = 12. <br>

<br> (ii) Even numbered red cards left in the pack are 2, 4, 8, 10 of hearts and 2, 4, 8, 10 of diamonds. <br>

Total number of even numbered red cards in the remaining pack = 8. <br>

The number of outcomes favourable to the event 'an even numbered red card'= 8. <br>

=8/40=1/5

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