if all sides of a rhombus are 13cm and one diagonal is 24cm, find the area
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A=1/2×d√4p^2-d^2
=1/2×24√4(13)²-24²
=120sq.cm
=120sq.cm
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area of rhombus =2 x area of traingle
area of triangle =root{s(s-a)(s-b)(s-c)}
s=(13+13+24)/2=25
now,
area of traingle =root{25 x 12 x 12 x 1}
=5 x 12 cm^2
hence area of rhombus =2 x 5 x 12
=120cm^2
area of triangle =root{s(s-a)(s-b)(s-c)}
s=(13+13+24)/2=25
now,
area of traingle =root{25 x 12 x 12 x 1}
=5 x 12 cm^2
hence area of rhombus =2 x 5 x 12
=120cm^2
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