Math, asked by poojagujja6493, 1 year ago

If all the numbers from 501 to 700 are written, what is the total number of times the digit 6 appears

Answers

Answered by tylik13williams
4

Answer:

= 10 + 10 + 100 + 10 + 10 = 140

Step-by-step explanation:

Answered by Aditya070303
6

Here we go!

Starting at 501, we have 20 sixes to get to 600. There is one six for every ten, and an extra for all of the numbers that start with 60. (506, 516, 526, 536, 546, 556, 560, 561, 562, 563, 564, 565, 566, 567, 568, 569, 576, 586, 596)

At 600, every number has at least one six except 700. That makes for 99 sixes.

After that, we know we have 20 extra sixes from the ones place and tens place. 99 + 20 = 119.

Total = 119 + 20  = 139 sixes

Hope it helps...

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Aditya070303: Answer will be 139...
I mistakenly typed 159.
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