Question

If alpa beta gamma are zeros of 4x^3-2x^2+x-1 then find alpa^-1 beta /-1 gamma^-1

Answer 1

$\frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } =$

$\frac{ \alpha \beta + \beta \gamma + \gamma \alpha }{ \alpha \beta \gamma }$

$= \frac{ 1}{ 1} = 1$