Question

If alpha=-2 and beta=1/3 then find p(x)?


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Answer 1

Answer:

If alpha and Beta are the zeroes  of the polynomial  x^2-p(x+1)-c,  find the value of (alpha +1)(beta+1)

 

x2 - p(x + 1) - c  

= x2 - px - p - c  

 

Comparing with ax2 + bx + c, we get

a= 1 , b = -p and c = - p - c

 

α and β are the zeroes of the given polynomial.

 

→ α + β = -b/a = -(-p)/1 = p

and αβ = c/a = -p - c / 1 = -p - c

 

To find: (α + 1)(β + 1)  

(α + 1)(β + 1) = αβ + α + β + 1

                     = - p - c + p + 1  

                     = 1 - c

Step-by-step explanation:

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