If alpha and 1by alpha are the zeroes of the
polynomial 4x*2 -2x + (k-4) then find the
value of k
Give correct answe
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Answers
Answered by
2
Answer:
hey mate here is your answer pls mark it as brainlist........
Step-by-step explanation:
compare 4x square - 2x + (k-4) with
ax square + bx + c
a = 4
b = -2
c = k-4
product of zeroes = c/a
alpha into 1/alpha = (k-4) /4
1 = (k-4) /4
4 = k-4
4+4 = k
8 = k
therefore
k = 8
Answered by
0
⏩welcome to the concept of polynomials.
Compare the polynomial
4x² - 2x + ( k - 4 )
with ,
ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
I hope it help you ❤️
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