Math, asked by riyaz112, 1 year ago

If alpha and 1by alpha are the zeroes of the
polynomial 4x*2 -2x + (k-4) then find the
value of k

Give correct answe

I will mark brainliest​

Answers

Answered by rajenderchipa
2

Answer:

hey mate here is your answer pls mark it as brainlist........

Step-by-step explanation:

compare 4x square - 2x + (k-4) with

ax square + bx + c

a = 4

b = -2

c = k-4

product of zeroes = c/a

alpha into 1/alpha = (k-4) /4

1 = (k-4) /4

4 = k-4

4+4 = k

8 = k

therefore

k = 8

Answered by Anonymous
0

⏩welcome to the concept of polynomials.

Compare the polynomial

4x² - 2x + ( k - 4 )

with ,

ax² + bx + c ,

a = 4 ,

b = - 2 ,

c = k - 4 ,

Product of the zeroes = c/a

Alpha × 1/alpha = ( k - 4 ) / 4

1 = ( k - 4 ) / 4

4 = k - 4

4 + 4 = k

8 = k

Therefore ,

k = 8

I hope it help you ❤️

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