Question

If alpha and beeta are roots of x^2-3x+2 then the equation whose roots are alpha^6 and beeta^6 is:-
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Answer 1

Answer:

x²-3x+2=0

x²-2x-x+2=0

x(x-2)-1(x-2)=0

(x-2)(x-1)=0

x-2=0,x-1=0

x=2,x=1

so,2 and 1 are the roots of given equation

letà=2 and ß=1

Now,à⁶=2⁶=64 and ß⁶=1⁶=1

required quadratic equation is

x²-(sum of roots) x+product of roots=0

x²-(64+1)x+64×1=0

x²-65x+64=0

Answer 2

Step-by-step explanation:

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