Question

If alpha and Beeta are the roots of x^2+7x+10=0
what is the value of alpha - beeta​

Answer 1

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies$ $\sf\red{given\:equation\:is\:x^2+7x+10=0}$

$\implies$ $\sf\red{we\:know\:that\:\alpha +\beta =\dfrac{-b}{a}}$

                         $\sf\red{\alpha \beta =\dfrac{c}{a}}$

$\implies\sf{now\:\alpha +\beta =-7}$

              $\sf\red{\alpha \beta =10}$

$\sf\red{asking\:\alpha -\beta \:so,}$

$\implies$ $\sf\red{\alpha -\beta =(\alpha +\beta )^2+2\alpha \beta }$

               $\sf\red{=(-7)^2+2(10)}$

               $\sf\red{=49+20}$

               $\sf\red{=69\:is\:your\:answer}$