Question

If alpha and beeta are the zeroes of x^2-3x-2 then find the quadratic polynomial whose zeroes are 1/2alpha+beta and 1/2beta+alpha

Answer 1

Answer:

x^2-9/2x+3

Step-by-step explanation:

Alpha=A and bita=B (let)

A+B=3, AB=-2(from 1st polynomial)

Then required polynomial is

X^2+(1/2A+B+1/2B+A)x+(1/2A+B)(1/2B+A)

Now solve this by using those value