Question

if alpha and beeta are the zeros of 4x^2-2x+(k-4).find k​

Answer 1

Answer:

k=8

Step-by-step explanation: Zeroes should be alpha and 1/alpha.

Alpha(1/alpha)= c/a = k-4/4.

1=k-4/4 (since alpha got cancelled by alpha)

k-4=4

k=4+4

k=8.

Answer 2

Answer:

=k-4=4

=k=4+4

=so k = 8.

=ans = k =8.

thanks. hope it helped.