Question

if alpha and beeta are zeros of the polynomial 6y^2-7y+2 find a quadratic polynomial whose zeros are 2alpha and 2 beeta​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given alpha and beta are zeroes of 6y²-7y+2

therefore Alpha+beta=-(-7/6)

=7/6

Alpha × beta = c/a = 2/6=1/3

Therefore the new polynomial with zeroes 2 alpha+2 beta is

y²-(2alpha+2beta)y+2alpha×2beta

y²-(2[alpha + beta])y+4 alpha beta

y²-(2×7/6)y+4/3

y²-14/6y+4/3

y²-7y/3 + 4/3

1/3(3y²-7y+4) {took LCM} is the required polynomial.

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