if alpha and beta are 0s of a quadratic polynomial x^2-x-30 the form of a quadratic polynomial whose 0s are 2-alpha and 2-beta
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Frst we have to find zeroes of the eqn
x^2-x-30=0
So
b^2-4ac=D^2
1-(-120)=D^2
1+120=D^2
So D=11
Now value of alpha and beta will be
-b±rootD/2a
1±11/2
So we get
Alpha =6 and beta =-5
So polynomial whose zeroes are 2 alpha and 2 beta will be
Alpha =2×6=12
Beta=2×-5=-10
WE know that
Eqn = x^2-(alpha+beta)x+alpha×beta
So x^2-2x-120
Hope it will help u
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