if alpha and beta are roots of the polynomial x square minus 25, find the polynomial who's root are 1 plus aplpha and 1 plus beta
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Answered by
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HERE IS YOUR ANSWER
=x²-25
=(x)²-(5)²
[USING a²-b²=(a+b)(a-b) ]
=(x+5)(x-5)
x+5=0
x= -5
α= -5
x-5=0
x=5
β=5
===============================
ROOTS OF THE POLYNOMIAL ARE :
α= -5
β= 5
===============================
NEW ROOTS :
=1+α
=1-5
= -4
AND
=1+β
=1+5
=6
===============================
THE NEW ROOTS ARE -4 AND 6
===============================
SUM OF ROOTS :
= (1+α)+(1+β)
= -4+6
=2
PRODUCT OF ROOTS:
=(1+α)(1+β)
= -4×6
= -24
===============================
REQUIRED POLYNOMIAL :
=x²-(sum of roots)x+(product of roots)
=x²-(2)x+(-24)
=x²-2x-24
===============================
SO THE REQUIRED POLYNOMIAL IS x²-2x-24
===============================
HOPE THIS HELPS YOU ☺
HERE IS YOUR ANSWER
=x²-25
=(x)²-(5)²
[USING a²-b²=(a+b)(a-b) ]
=(x+5)(x-5)
x+5=0
x= -5
α= -5
x-5=0
x=5
β=5
===============================
ROOTS OF THE POLYNOMIAL ARE :
α= -5
β= 5
===============================
NEW ROOTS :
=1+α
=1-5
= -4
AND
=1+β
=1+5
=6
===============================
THE NEW ROOTS ARE -4 AND 6
===============================
SUM OF ROOTS :
= (1+α)+(1+β)
= -4+6
=2
PRODUCT OF ROOTS:
=(1+α)(1+β)
= -4×6
= -24
===============================
REQUIRED POLYNOMIAL :
=x²-(sum of roots)x+(product of roots)
=x²-(2)x+(-24)
=x²-2x-24
===============================
SO THE REQUIRED POLYNOMIAL IS x²-2x-24
===============================
HOPE THIS HELPS YOU ☺
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