Question

if alpha and beta are roots of x^2+6x+9 =0 then equation vwhose roots are 1/alpha and 1/beta​

Answer 1

Answer:

$x^{2}+\frac{2x}{3} +\frac{1}{9}$

Step-by-step explanation:

Roots of eqn you have provided are -3 and -3,(by factorising:(x+3)(x+3)=x^2+6x+9=0 )

Therefore equation with roots 1/alpha and 1/beta, would be :

(x-1/alpha)*(x-1/beta),

alpha=beta=-3

The final answer we get is $x^{2}+\frac{2x}{3} +\frac{1}{9}$

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