if alpha and beta are the quadratic polynomial f of x is equal to X square + X - 2 then find the value of one by Alpha minus one by beta
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f(x) = x² + x - 2
1/α - 1/β = (β - α)/αβ
α + β = -(Coefficient of x)/Coefficient of x²
=> α + β = -1
αβ = Constant/Coefficient of x²
=> αβ = -2
(α + β)² = α² + 2αβ + β²
=> (-1)² = α² + 2(-2) + β²
=> 1 = α² - 4 + β²
=> α² + β² = 5
(α - β)² = α² + β² - 2αβ
=> (α - β)² = 5 - 2(-2)
=> (α - β)² = 9
=> α - β = 3
β - α = (-1)(α - β)
β - α = (-1)(3) = (-3)
Substituting, we get
(-3)/(-2)
or
3/2
vraj9062:
In last how will you get bèta minus alpha
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