If alpha and beta are the roots of the equation 3x²+7x-2=what are the value of alpha)beta+beta/alpha
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3x^2 - 7x - 2 = 0
D = b^2 - 4ac
D = (7)^2 - 4(3)(2)
D = 49 - 24
D = 25
Now ,
x = - b + root (D) / 2a
x = -b + root (D) / 2a , -b - root (D) / 2a
x = -(-7) + root(25) / 2(3) , -(-7) - root(25) / 2(3)
x = 7 + 5 / 6 , 7 - 5 / 6
x = 12 / 6 , 2 / 6
x = 2 , 1 / 3
let 2 be alpha and 1 / 3 be beta
alpha x beta = 2 x 1/3
= 2/3
beta / alpha = 1/3 / 2
= 1 / 3 x 1 / 2 : 1 / 6
Now , alpha x beta + beta / alpha
= 2/3 + 1/6
= 4 + 1 / 6 : 5 / 6
Therefore , 5/6 is ANSWER .
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