Question

If alpha and beta are the roots of the equation (x-a) (x-b) =c andc is not equal to 0 then the roots of the equation (x-alpha) (x-beta)?

Answer 1

$(x - a )(x - b) = c \\ {x}^{2} - (a + b)x + (ab - c) = 0 \\ so \: if \: \alpha \: and \: \beta are \: roots \: so \\ \alpha + \beta = a + b \\ \alpha \beta = ab - c \\ so \: eqn \: \\ (x - \alpha )(x - \beta ) \: becomes \: \\ {x }^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ {x}^{2} - (a + b)x + (ab - c) = 0 \\ roots \\ = \frac{(a + b)( + - ) \sqrt{(a + b) {}^{2} - 4(ab - c) } }{2}$
these are roots of eqn...
mark as brainliest if helped

Answer 2

Answer:

a+c,b+c

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