Question

if alpha and beta are the roots of x²-6x+4=0 find the valve of alpha -beta the whole square​

Answer 1

Answer:

Step-by-step explanation:

If ,α β are roots of quadratic eqn. 2. 0, ax bx c. + + = then. (. )( ) 0. a x x α β ... the valves of α β ... det (A)=3(4-0)-2(-20-0)+1(5-3)=3(4)-2(-20)+1(2)=12+40+2=54 ... It is a square matrix in which all the elements below the principle diagonal ... i.e. 6 x2 – 6x – 72 > 0.

mark me as brainliest

Answer 2

Answer:

Given:- a and b are the roots of the quadratic equation x^2-6x+4

To find:- (a-b)^2

Solution:-

we know that,

Sum of zeroes= -(coefficient of x)/coefficient of x^2

a+b= -(-6)/1

a+b= 6

(a+b)^2= a^2+b^2+2ab

(6)^2= a^2+b^2+2×4

36-8= a^2+b^2

a^2+b^2= 28

Now product of zeroes

ab= constant/coefficient of x^2

ab= 4

now (a-b)^2= a^2+b^2-2ab

= 28-2×4

= 28-8

= 20

hope it helps you

please mark brainliest