if alpha and beta are the two zeros of polynomial x2+x+1 then find A2+B2
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Answered by
2
The answer is given below :
The given polynomial is (x² + x + 1).
Since, α and β are the roots of the polynomial, we get
α + β = (- 1)/1
⇒ α + β = - 1 .....(i)
and
αβ = 1/1
⇒ αβ = 1 .....(ii)
Now,
α² + β²
= (α + β)² - 2αβ
= (- 1)² - (2 × 1)
= 1 - 2
= - 1
Thank you for your question.
The given polynomial is (x² + x + 1).
Since, α and β are the roots of the polynomial, we get
α + β = (- 1)/1
⇒ α + β = - 1 .....(i)
and
αβ = 1/1
⇒ αβ = 1 .....(ii)
Now,
α² + β²
= (α + β)² - 2αβ
= (- 1)² - (2 × 1)
= 1 - 2
= - 1
Thank you for your question.
Answered by
8
HEY YOUR ANSWER IS .....
It is given that alpha and beta are the zeros of polynomial x^2 + x + 1 .....
So ,
alpha+beta=-b/a =-1/1 = -1
And.....
alpha×beta=c/a =1/1 = 1
Comparing with p(x) = x^2+x+1
Here , a = 1 , b = 1 and c = 1 .
So , (a+b)^2 = a^2 +2ab+b^2
So , 4 = 1 +2+1
So , 4 = 4 .
So , LHS= RHS .
It is given that alpha and beta are the zeros of polynomial x^2 + x + 1 .....
So ,
alpha+beta=-b/a =-1/1 = -1
And.....
alpha×beta=c/a =1/1 = 1
Comparing with p(x) = x^2+x+1
Here , a = 1 , b = 1 and c = 1 .
So , (a+b)^2 = a^2 +2ab+b^2
So , 4 = 1 +2+1
So , 4 = 4 .
So , LHS= RHS .
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