if alpha and beta are the zeroes of polynomial 5x^2-3x-1 then find the value of 1/alpha +1/beta +2
Answers
Answered by
10
Hello users .....
---------------------------------------------
We know that:
For a quadratic equation : ax² + bx + c = 0 :
if α and β Are the roots of equation.
sum of roots (α+β) = -b / a
And
product of roots (αβ) = c / a
Here,
for given quadratic equation
5x² - 3x - 1 = 0
here,
a = 5 , b = -3 and c = -1
Sum of roots (α+β) = -b / a
=> α+β = -(-3)/(5) = 3 / 5
And
product of roots (αβ) = c / a
=> αβ = (-1) / 5 = -1 / 5
Now,
1 / α + 1 / β = (α+β) / αβ ( taking LCM )
=> 1 / α + 1 / β = (3/5) / (-1/5)
=> 1 / α + 1 / β = 3 / -1
=> ( 1 / α + 1 / β ) = -3
=> ( 1 / α + 1 / β ) + 2 = -3 + 2
=> ( 1 / α + 1 / β ) + 2 = -1 Answer
Hope it helps :)
---------------------------------------------
We know that:
For a quadratic equation : ax² + bx + c = 0 :
if α and β Are the roots of equation.
sum of roots (α+β) = -b / a
And
product of roots (αβ) = c / a
Here,
for given quadratic equation
5x² - 3x - 1 = 0
here,
a = 5 , b = -3 and c = -1
Sum of roots (α+β) = -b / a
=> α+β = -(-3)/(5) = 3 / 5
And
product of roots (αβ) = c / a
=> αβ = (-1) / 5 = -1 / 5
Now,
1 / α + 1 / β = (α+β) / αβ ( taking LCM )
=> 1 / α + 1 / β = (3/5) / (-1/5)
=> 1 / α + 1 / β = 3 / -1
=> ( 1 / α + 1 / β ) = -3
=> ( 1 / α + 1 / β ) + 2 = -3 + 2
=> ( 1 / α + 1 / β ) + 2 = -1 Answer
Hope it helps :)
astha37:
the question is 1/alpha+1/beta+2
Similar questions
English,
8 months ago
Social Sciences,
8 months ago
Geography,
1 year ago
Math,
1 year ago
English,
1 year ago