if alpha and beta are the zeroes of polynomial 6x²+5x+k such that alpha-beta=1/6.Find the value of k
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Answer:
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Step-by-step explanation:
Given polynomial : 6x² + 5x + k
Comparing with ax² + bx + c we get,
- a = 6
- b = 5
- c = k
α, β are the zeroes of the polynomial
Sum of zeroes = α + β = - b / a = - 5 / 6
Product of zeroes = αβ = c / a = k / 6
Given :
α - β = 1/6
Using algebraic identity ( α + β )² - ( α - β )² = 4αβ
=> ( - 5 / 6 )² - ( 1 / 6 )² = 4( k/6 )
=> 25/36 - 1/36 = 4k/6
=> ( 25 - 1 ) / 36 = 4k/6
=> 24 / 36 = 4k/6
=> 24/36 × 6 = 4k
=> 24/6 = 4k
=> 4 = 4k
=> 1 = k
=> k = 1
Therefore the value of x is 1.
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