Question

If alpha and beta are the zeroes of polynomial ax^2+bx+c find
Alpha^2/beta + beta^2/alpha

Answer 1

Answer:

=(b²-ac)/c

Step-by-step explanation:

α+β=-b/a,αβ=c/a

α²/β+β²/α=α³+β³/αβ

=(α²+β²+αβ)/αβ

=[ (α+β)²-αβ ]/αβ

=[(-b/a)²-c/a]/(c/a)

=(b²/a²-c/a)/(c/a)

=a/c*a(b²-ac)

=(b²-ac)/c