If alpha and beta are the zeroes of polynomial p(x)=3x²+2x+1. Find the polynomial whose zeroes are (1-alpha/1+beta) and (1-beta/1+beta)
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Factorise
3x^2+2x+1
=(3x+1)(x+1)
Alpha and Beta value:
3x+1=0
3x=-1
x=-1/3=α
x-1=0
x=1=β
Find the polynomials of zeroes are
(1-α/1+β)
=(1-(-1/3)/1+1
=3+1/3/2
=4/3/2
=3
1-β/1+β
=1-1/1+1
=0/1
3x^2+2x+1
=(3x+1)(x+1)
Alpha and Beta value:
3x+1=0
3x=-1
x=-1/3=α
x-1=0
x=1=β
Find the polynomials of zeroes are
(1-α/1+β)
=(1-(-1/3)/1+1
=3+1/3/2
=4/3/2
=3
1-β/1+β
=1-1/1+1
=0/1
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