Math, asked by shahrukh31, 11 months ago

if alpha and beta are the zeroes of polynomial x2-6x+a then find the value of if 3alpha+2beta =20


shahrukh31: ok

Answers

Answered by armanparate
14

Polynomial P(x) = x² - 6 x + a

Given α and β are the roots. To find a , if 3 α + 2 β = 20. ---(1)


From the quadratic expression:

α + β = 6 ---(2)

and α β = a --- (3)


Multiply equation (2) by 2 and subtract from (1) to get:

α = 20 -12 = 8


Substitute this value in(2) to get:

β = 6-8 = -2


Substitute these in (3) to get: a = α β = -16.


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shahrukh31: ans my q
armanparate: Which q
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shahrukh31: find the ar of quad whose circumference is 44......??
shahrukh31: hallloooooo....
armanparate: Let radius be r cm

We are given, Circumference, 2πr = 44
                          so, πr = 22
                        so, 22/7*r = 22
                             r = 7 cm

So, area of Quadrant = 1/4 * πr²
                                   = 1/4 * 22/7 * 7*7
                                   = 22*7/4
                                   = 154/4 = 38.5 cm²
                                              

Read more on Brainly.in - https://brainly.in/question/2789146#readmore
Answered by Anonymous
4

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@Answer..


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Polynomial   P(x) = x² - 6 x + a


Given  α and  β  are the roots.     To find a , if 3 α + 2 β = 20.  ---(1)



From the quadratic expression:


   α + β = 6       ---(2)


   and   α β = a  --- (3)



Multiply equation (2) by 2 and subtract from (1) to get:


   α = 20 -12 = 8



Substitute this value in(2) to get:    


    β = 6-8 = -2   



Substitute these in (3) to get:    a = α β = -16.




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shahrukh31: what to add in x4+2x3-2x2+x-1 so it diisible by x2+2x-3......
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