if alpha and beta are the zeroes of polynomial x2-6x+a then find the value of if 3alpha+2beta =20
Answers
Polynomial P(x) = x² - 6 x + a
Given α and β are the roots. To find a , if 3 α + 2 β = 20. ---(1)
From the quadratic expression:
α + β = 6 ---(2)
and α β = a --- (3)
Multiply equation (2) by 2 and subtract from (1) to get:
α = 20 -12 = 8
Substitute this value in(2) to get:
β = 6-8 = -2
Substitute these in (3) to get: a = α β = -16.
We are given, Circumference, 2πr = 44
so, πr = 22
so, 22/7*r = 22
r = 7 cm
So, area of Quadrant = 1/4 * πr²
= 1/4 * 22/7 * 7*7
= 22*7/4
= 154/4 = 38.5 cm²
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Polynomial P(x) = x² - 6 x + a
Given α and β are the roots. To find a , if 3 α + 2 β = 20. ---(1)
From the quadratic expression:
α + β = 6 ---(2)
and α β = a --- (3)
Multiply equation (2) by 2 and subtract from (1) to get:
α = 20 -12 = 8
Substitute this value in(2) to get:
β = 6-8 = -2
Substitute these in (3) to get: a = α β = -16.